Suppose that the distance an aircraft travels along a runway before takeoff is given by Upper D equals (5 divided by 3 )t squaredD=(5/3)t2, where D is measured in meters from the starting point and t is measured in seconds from the time the brakes are released. The aircraft will become airborne when its speed reaches 300300 km divided by hkm/h. How long will it take to become airborne, and what distance will it travel in that time?

a. Time=25seconds

b.distance=1041.67m

Explanation:

a.The equation for in terms of m/s is after conversion.

To find when speed reaches 300km/hr=83.33m/s, we find and solve for

b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.

#To find distance travelled in that time , we substitute for in our distance equation:

Hence the distance of the plane before it gets airborne is 1041.67m

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards