If the volume of a sample of a gas is increased 5 times the original volume while the temperature is held constant, what happens to the pressure of the gas?

Therefore,

The pressure of the gas will be 1/5th of the original.

Explanation:

Given:

Let V₁ , P₁, and T₁ be the original Volume , Pressure and Temperature,

Now it Changes to V₂ , P₂ , and T₂

To Find:

What happens to the new pressure

Solution:

Combined Gas Law:

The combined gas law combines the three gas laws:  

Boyle's Law, Charles' Law, and Gay-Lussac's Law.  

It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.

Hence,

Substituting the values  we get, T₁ and T₂ , V₁ will get cancelled,

That is Pressure decreases by

Therefore,

The pressure of the gas will be 1/5th of the original.

its c i just checked it