An object attached to an ideal massless spring is pulled across a frictionless surface. If the spring constant is 45 N/m and the spring is stretched by 0.88 m when the object is accelerating at what is the mass of the object?

Incomplete questions

We are not given the acceleration of the motion , check attachment for complete question

Explanation:

Given that

Spring constant (k)=45N/m

The extension (e)=0.88m

Also given that the acceleration is 2m/s²

Force by the spring is given as

Using hooke's law

F=ke

F=45×0.88

F=39.6N

Now this force will set the object in motion, now using newton second law of motion

F=ma

Then, m=F/a

m=39.6/2

m=19.8kg

The mass of the object is 19.8kg which is approximately 20kg

The correct option is C

explanation:

as the height from which the ruler was dropped increased, the speed of the ruler at ryan's hand increased.