The surface charge density on an infinite charged plane is - 2.10 ×10−6C/m2. A proton is shot straight away from the plane at 2.40 ×106m/s. How far does the proton travel before reaching its turning point?

Explanation:

Formula to calculate electric field because of the plate is as follows.

         E =

            =

           =

Now, we will consider that equilibrium of forces are present there. So,

                   ma = qE

       a =

          =

According to the third equation of motion,

or,      d =

             =

             = 0.254 m

Thus, we can conclude that the proton will travel 0.254 m before reaching its turning point.

do you have a formula possibly