A rock is whirled on the end of a string in a horizontal circle of radius R with a constant period T. If the radius of the circle is reduced to R/3, while the period remains T, what happens to the centripetal acceleration of the rock

The centripetal acceleration of the rock is decreases by a factor of 3.

Explanation:

Given that,

Radius of circle

Time period = T

Radius of new circle

We need to calculate the velocity

Using formula of velocity

The time period for new circle

The time period remains same.

Put the value in the equation

The acceleration of the rock is

We need to calculate the acceleration of the new rock

Using formula of acceleration

Put the value into the formula

Hence, The centripetal acceleration of the rock is decreases by a factor of 3.

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

probably not if net force is zero