A straight wire segment 2 m long makes an angle of 30degrees with a uniform magnetic field of 0.37 T. Find the magnitude of the force on the wire if it carries a current of 2.3 A.

0.999 N.

Explanation:

From the question,

The formula for the force on a conductor carrying current in a magnetic field is given as,

F = BILsinФ Equation 1

Where F = force on the wire, B = magnetic field, I = current carried by the wire,   L = length of the wire, Ф = angle between the wire and the magnetic field.

Given: B = 0.37 T, I = 2.3 A, L = 2 m, Ф = 30°

Substitute into equation 1

F = 0.37(2.3)(2)(sin30)

F = 0.37(2.7)(2)(0.5)

F = 0.999 N.

Hence the force on the wire = 0.999 N.

the answer would be a

the amount of current in the coil