A bomb falls with velocity v(t)=C(1−e−kt), where C and k are constants. What is the terminal velocity of the bomb? That is, what is the maximum valocity the bomb can reach regardless of the height of the bomber?

The terminal velocity is equal to C.

Explanation:

Making the assumption that k and t are positive, we then have that -kt is negative. The value of e^(-kt) will be equal to 1/(e^(kt))

If t increases, e^(kt) will increase exponentially and its reciprocal 1/(e^(kt)) will approach zero.

So, we have:

v(t) = C*(1-0)

v(t) = C*(1)

v(t) = C

Therefore, C is the terminal velocity.

convex lenses are thicker at the middle. rays of light that pass through the lens are brought closer together (they converge). a convex lens is a converging lens. when parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.

the answer would be c. motion and direction

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