How much thermal energy is needed to raise the temperature of 4.0 kg of water from 25°C to 75°C?

Q= 840,000 J

Explanation: We will use the formula for heat to solve this problem Q= mc∆T, where the specific heat or "c" of water is 4200 J/kg°C. The change in temperature ∆T is equal to ∆T = ( 75°C-25°C) = 50°C

Q= 4.0 kg ( 4200 J/kg°C) ( 50°C)

= 840,000J

Cancel out the units of kg and °C so the remaining unit is in joules.

are there options? cause you ain’t. real specific

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.