Mike walked 450 m west. he then turned and walked 150 m to the east in 300 seconds. what was his velocity?

Velocity, v = 1 m/s

Explanation:

Given that,

Initially Mike walked 450 m due west and then he turned and walked 150 m to the east.

Time taken, t = 300 s

The displacement of Mike is equal to the difference in final position and the initial position.

d = 450 - 150

d = 300 m

Let v is his velocity. It is equal to the net displacement divided by total time taken.

v = 1 m/s

So, the velocity of Mike is 1 m/s. Hence, this is the required solution.

attach the statements so i can answer : )

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s