A satellite that is in a circular orbit 230 km above the surface of the planet Zeeman-474 has an orbital period of 89 min. The radius of Zeeman-474 is 6.38 × 10 6 m. What is the mass of this planet?

Mass of the planet = 6.0 ×

Explanation:

Time period = 2π (R + h) / v

Orbital speed (v) = √GM / (R + h)

T² = 4π² (R + h)² / (GM/ (R + h))

    = 4π² (R + h)³ / GM

  making m the subject of the formula

m = 4π² (R + h)³ / GT²

   = 4π² ( 6.38 × + 230 × 10³ )³ / ( 6.67 × ) × (89 × 60)²

    = 4π² ( 6610000)³ / ( 6.67 × ) × (89 × 60)²

    = 5.99 ×

     = 6.0 ×

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min

answercollision;