How much work is needed to push a 117- kg packing crate a distance of 2.75 m up an inclined plane that makes an angle of 28 o with the horizontal, when inclined plane is frictionless

Explanation:

The minimum total work is the work needed to counteract the work associated with the weight:

Given Information:  

mass of crate = m = 117 kg

distance = d = 2.75 m  

Inclined plane angle = θ = 28°

Required Information:  

Work done = W = ?

Work done = 1480.3 N.m

Explanation:

Refer to the attached image, since there is no friction, the only force acting on the crate is the force in the downward direction given by

Fy = mgsin(θ)

Fy = 117*9.8*sin(28°)

Fy = 538.3 N

Now as we know work done is given by

W = Fy*d

W = 538.3*2.75

W = 538.3*2.75

W = 1480.3 N.m

Therefore, 1480.3 N.m of work is required to push a 117 kg  of crate to a distance of 2.75 m up an inclined plane making an angle of 28° with the horizontal surface.

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia