Estimate the average force exerted by a shot-putter on a 7.0-kg shot if the shot is moved through a distance of 2.2 m and is released with a speed of 12 m/s .

229.11 N

Explanation:

Mass of the shot (m) = 7.0 kg

Distance moved by the shot (S) = 2.2 m

Initial velocity of the shot (u) = 0 m/s (assume)

Final velocity of the shot (v) = 12 m/s

First we will determine the acceleration of the shot using the following equation of motion.

So, the acceleration of the shot is 32.73 m/s².

Now, using Newton's second law, the force acting on the shot is equal to the product of mass and acceleration. So,

Force = Mass × Acceleration

Therefore, the average force exerted by the shot-putter is 229.11 N.

specific latent heat of fusion, lf, of a substance is defined as the amount of heat required to change a unit mass of the substance from solid to liquid state, without any change in the temperature.

explanation:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day