) (Problem 2.35 from text) Consider a light wave having a phase velocity of 3x10-8 m/s and a frequency of 6x1014 Hz. What is the shortest distance along the wave between any two points that have a phase difference of 300

The shortest distance covered by the wave between the given points is .

Explanation:

The Phase velocity () of any wave can be written as

where '' is the angular velocity and '' is the wave number.

Also, if '' is the frequency of the wave, then

Given, , and the phase difference between two points is .

If the wave travels by the shortest distance of between these points, then we can write

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force