2) Suppose you have a 120.0-kg wooden crate resting on a wood floor, with coefficient of static friction 0.500 between these wood surfaces. (a) What maximum force can you exert horizontally on the crate without moving it? (b) If you continue to exert this force once the crate starts to slip, what will its acceleration then be? The coefficient of sliding friction is known to be 0.300 for this situation

Explanation:

Given data

Mass m=120.0 kg

Coefficient of static friction

The coefficient of sliding friction

For Part (a) Maximum force

According to Newtons second law the net force aced on the body is given by

The friction force is given by

Conclude that

For Part (b) Acceleration

The acceleration due to dynamic friction is given by:

The dynamic friction is given by:

So the acceleration given by

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.