In a ballistics test, a 25 g bullet traveling horizontally at 1200m/s goes through a 30 cm thick 350 kgstationary target and emerges with a speed of 900 m/s. The target is free to slide on a smoothhorizontal surface.
(a) How long is the bullet in the target?
1 s
What average force does it exert on the target?
2 N (magnitudeonly)
(b) What is the target's speed just after the bullet emerges?
3 m/s

Answer is c because in exothermic reactions, energy releases.in cellular respiration,atp+h20 (water) = adp+ pi + energyso celullar respiration is exothermic and releases energy

The low lands i believe

You yeah with the side of the yeah with a little bit of yeah.

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.