Afeather is dropped onto the surface of the moon. how far will the feather have fallen if it reaches in 9.00 seconds? given: g on moon = -1.6 meters/second squared

The distance traveled while accelerating from rest is

                           D  =  1/2 a t²    .

For this problem, we shall totally ignore air resistance.
We do so completely without any reservation or guilt,
because we know that there is no air on the moon.

                     D  =  (1/2) · (1.6 m/s²) · (9 sec)²

                         =       (0.8 m/s²) · (81 s²)

                         =        (0.8 · 81) m

                         =            64.8 meters  .

(That's about 213 feet !  The astronaut must have dropped the feather
from his spacecraft while he was aloft ... either just before touchdown
or just after liftoff.)

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