A current of 55.9 mA flows in a silver wire of diameter 4.33 mm. Find the electric field strength inside the wire. The conductivity of silver is 6.25 × 10 7 Ω − 1 m − 1 .

6.07 * 10^(-5) N/C

Explanation:

Parameters given:

Diameter = 4.33 mm

Radius = 2.165 mm = 0.002165 m

Conductivity, σ = 6.25 * 10 (Ωm)^(-1)

Current, I = 55.9 mA = 0.0559 A

Electric field Intensity, E, is given as:

E = I/Aσ

Where A = Area

E = 0.0559/(π*0.002165²*6.25*10^7)

E = 0.0559/919

E = 6.08 * 10^(-5) N/C

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