What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 47.0 nC placed between q1 and q2 at x3 = -1.075 m ? Your answer may be positive or negative, depending on the direction of the force.

The force between charges is illustrated by Coulomb's law. The force exerted on charge 3 by the first and second charge is

The force between charges is calculated using:

Where:

The given parameters are:

at

at

at

Calculate the distance between the first and third charges

The force between the first and third charges is:

So, we have:

Calculate the distance between the second and third charges

The force between the second and third charges is:

So, we have:

The net force is then calculated as follows:

This gives:

Hence, the net force on the third charge is

Read more about net forces at:

link

Incomplete question, check attachment for completed question

Explanation:

The force of attraction between two forces are given as

F=kQq/r²

i think its c if i'm wrong