A particle is moving with a velocity of 60.0 m/s in the positive x direction at t= 0. Between t= 0 and t= 15.0 s the velocity decreases uniformly to zero. What was the acceleration during this 15.0-s interval? What is the significance of the sign of your answer?

Acceleration of the object is given as

so here negative sign shows that the direction of acceleration is opposite to the velocity of the object

Explanation:

As we know that velocity decreases uniformly from maximum to zero

so here in this uniform deceleration we know that

now by using the equation of kinematics we have

so here negative sign shows that the direction of acceleration is opposite to the velocity of the object

i agree kid

explanation:

a

truck y has a greater velocity than truck x.