Three friends tie three ropes in a knot and pull on the ropes in different directions. Adrienne (rope 1) exerts a 20-N force in the positive x-direction, and Jim (rope 2) exerts a 40-N force at an angle 53∘ above the negative x-axis. Luis (rope 3) exerts a force that balances the first two so that the knot does not move.
a. Use equilibrium conditions to find F LonKx and F LonKy.
b. Use equilibrium conditions to determine the magnitude of F⃗ LonK.
c. Use equilibrium conditions to determine the angle θ that describes the direction of F⃗ LonK. Use positive values if the force is directed above the positive x-axis and negative values if it is directed below the positive x-axis.
d. Construct a force diagram for the knot.

Part a)

Part b)

Magnitude of the force is given as

Part c)

As we know that Y component of the force is negative so here the force is directed below the X axis

Explanation:

Part a)

Adrienne apply the force of 20 N along +X direction and Jim apply force of 40 N at 53 degree above negative X axis

so we will have

now let say the force exerted by Luis is F such that sum of all forces must be zero

now we have

so we have

Part b)

Magnitude of the force is given as

Part c)

As we know that Y component of the force is negative so here the force is directed below the X axis

So here we have

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

higher potential

explanation:

because it is in a high speed so it must move into a of high potential