Merry-go-rounds are a common ride in park playgrounds. The ride is a horizontal disk that rotates about a vertical axis at their center. A typical size is a diameter of 12 ft. A rider sits at the outer edge of the disk and holds onto a metal bar while someone pushes on the ride to make it rotate. Estimate a typical time for one rotation. (a) For your estimated time, what is the speed of the rider, in m/s? (b) What is the rider's radial acceleration, in m/s2? (c) What is the rider's radial acceleration if the time for one rotation is halved?

The answers to the question are;

(a) The speed of the rider for your estimated time of 6 s in m/s is 1.91 m/s

(b) The rider's radial acceleration, in m/s² is 2.006 m/s²

(c) The rider's radial acceleration = 8.03 m/s².

Explanation:

To solve the question, we note that

Angular velocity ω is the time to make a given change in the angle of an object per unit time.

Therefore ω =

Where:

θ =  Position angle

t = Time

S = Arc length

v = Linear velocity

r = Circle radius

Where the Diameter of the merry-go-round is 12 ft the circumference is given by

Circumference of merry-go-round = π×D = π × 12 ft  = 37.7 ft

If it takes 6 seconds make one revolution, then we have

ω₁   = 1.047 rad/s

(a) The speed is given by

v = r×ω₁ = 6 ft × 1.047 rad/s = 6.28 ft/s = ‪1.91 m/s

The speed of the rider for your estimated time of 6 s in m/s = 1.91 m/s

(b)  The radial acceleration in m/s² is given by

a = ω₁²×r = where r = 6 ft =  1.83 m

(1.047 rad/s)² × 1.83 m= 2.006 m/s²

The rider's radial acceleration, in m/s² = 2.006 m/s²

(c) If the time for one rotation is halved then the angular velocity is doubled and we have

ω₂ = = = = 2×ω₁ = 2×1.047 rad/s = 2.094 rad/s

The radial acceleration in m/s² is then given by

ω₂²× r = (2.094 rad/s)² × 1.83 m = 8.03 m/s²

The rider's radial acceleration = 8.03 m/s²

a women have faced negative attitudes in some areas , but other

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

happy to

pls mark as brainliest.