An observer stands at the tip of the dark blue arrow in the diagram below what is the view of the sun from the observer’s point of you

An observer stands at the tip of the dark blue arrow in the diagram the view of the sun from the observer’s point of you is the following

Explanation:

1.The region of complete shadow is called the umbra and the region of diffuse shadow is called the penumbra. These shadows are formed on the Earth during a solar eclipse and From the umbra we see a total eclipse while from the penumbra only a partial eclipse is visible.

2.There are four different types of solar eclipse, namely Partial eclipse, Annular eclipse, Total Eclipse and Hybrid Eclipse. A partial solar eclipse occurs when only part of the Sun is covered by the Moon which appears to take a “bite” out of the Sun.

3.Solar eclipses can only occur during a New Moon when the Moon moves between Earth and the Sun and the 3 celestial bodies form a straight line: Earth–Moon–Sun. There are between 2 and 5 solar eclipses every year. There are 3 kinds of solar eclipses: total, partial, and annular.

4.You can see from the two diagrams that there are two types of shadow; a crisp edged one formed by a point source of light and a rather more fuzzy one that is formed by a larger source. The region of deep, total shadow is called the UMBRA and the region of partial shadow is called the PENUMBRA.

5.umbra. The very darkest part of a shadow is the umbra. It's where the light source is completely blocked by the object in front of it.

6.The Moon's shadow actually has two parts:

Penumbra. The Moon's faint outer shadow. Partial solar eclipses are visible from within the penumbral shadow.

Umbra. The Moon's dark inner shadow. Total solar eclipses are visible from within the umbral shadow.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

see earlier answer