A 87 kgkg skydiver can be modeled as a rectangular "box" with dimensions 18 cmcm ×× 47 cmcm ×× 180 cmcm . If he falls feet first, his drag coefficient is 0.80. What is his terminal speed if he falls feet first? Use rho = 1.2 kg/m3 for the density of air at room temperature.

Therefore the terminal velocity = 1.45 m/s

Explanation:

Terminal velocity: Terminal velocity is the highest velocity of an object when it falls from rest trough a media.

= terminal velocity

w = weight of the object = mg

= drag coefficient=0.80

A= frontal area

= media density = 1.2 kg/m³

m = mass = 8 kg

g= acceleration due to gravity = 9.8 m/s²

Front area = length× breadth

                 = (18×47)cm²

                 =846 cm²

Therefore the terminal velocity

    =1.45 m/s

Therefore the terminal velocity = 1.45 m/s

yup its correct its: c) b b

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr