A block is placed on an inclined plane with an angle of inclination θ (in degrees) with respect to horizontal. The coefficient of static friction between the block and the inclined plane is 0.4. For what maximum value of θ will the block remain stationary on the inclined surface?

The maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°

Explanation:

Given;

coefficient of static friction, μ = 0.4

for the block to remain stationary on the inclined plane, force pushing the block upward must be equal to the force acting downwards.

μR = mgsinθ

μmgcosθ = mgsinθ

μcosθ = sinθ

μ = sinθ/cosθ

μ = tanθ

θ = tan⁻¹(0.4) = 21.8°

Therefore, the maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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