A compression at a constant pressure of 190 kPa is performed on 4.0 moles of an ideal monatomic gas (CV=1.5R). The compression reduces the volume of the gas from 0.24m^3 to 0.12m^3 What is the work done by the gas?

57 kJ

-23 kJ

23 kJ

-57 kJ

zero

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Ihope you find the answer

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward