A fixed end rectangular cantilever beam is subjected to 40 kg load at its end. The beam is 80 mm high, 20 mm wide and 0.5 m long. What is the maximum deflection of the beam if the material used is high modulus graphite/epoxy composite (fiber volume fraction is

The maximum deflection is 0.325 mm

Explanation:

we have the following data given:

m = 40 kg

L = 0.5 m

h = 80 mm = 0.08 m

b = 20 mm = 0.02 m

We calculate W:

W = m*g = 40 * 9.8 = 392.4 N

we will calculate the moment of inertia of the area which will be equal to:

I = (b*h^3)/12 = (0.02*0.08^3)/12 = 8.56x10^-7

The Young´s modulus is equal to:

E = (20*270)/(100) + (3.2*(100-20))/100 = 58.6x10^9 Pa

The deflection is equal to:

δ = (W*L^3)/(3*E*I) = (392.4 * (0.5^3))/(3*58.6x10^9*8.56x10^-7) = 0.000325 m = 0.325 mm

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y