A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. The same cart again traveling at 0.3 m/s collides with a different stationary object. This time the cart is at rest after the collision. In which collision is the impulse on the cart greater?A. The impulses are the same. B. The second collision. C. The first collision. D. Cannot be determined without knowing the mass of the cart. E. Cannot be determined without knowing the rebound speed of the first collision.

The second impulse is greater then the first impulse.

(B) is correct option.

Explanation:

Given that,

In first case,

Initial speed of cart = 0.3 m/s

Final speed of cart = -0.3 m/s

in second case,

Initial speed of cart = 0.3 m/s

Final speed of cart = 0 m/s

In first case,

We need to calculate the  impulse

Using formula of impulse

Put the value into the formula

In second case,

We need to calculate the new impulse

Using formula of impulse

Put the value into the formula

So, I'> I

Hence, The second impulse is greater then the first impulse.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)