The first hill of a roller coaster is 42 meters high. The top of the second hill of the one
coaster is 33 meters high. The mass of the roller coaster is 34,500 kg.
a. What is the velocity at the top of the second hill? Ignore friction and assume the
velocity at the top of the first hill is O m/s.
b. What type(s) of energy does the roller coaster have at the top of the second hill?

Part a)

Speed of the roller coaster is

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

Explanation:

As we know that there is no friction on the path

So here we can use mechanical energy conservation law

so we will have

Part a)

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

car a and b are moving in opposite directions

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  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂