For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser pointer (λ=680nm) through the slit onto a screen 5.5 m away, a diffraction pattern appears. The bright band in the center of the pattern is 8.0 cm wide. What is the width of the slit?

4.675×10^-6 m

Explanation: this is a question under the pattern gotten from an interference experiment.

The formulae below defines the experiment given

y = Rmλ/d

Where y = distance between the center fringe and any other fringe in the pattern = 8cm = 0.08m

m = position of fringe = 1 ( this is because we have only one central band)

λ = wavelength of light used for experiment = 680nm = 6.8×10^-7m

d = width of slit =?

R = distance between slits and screen = 5.5 cm = 0.055m

By substituting the parameters, we have that

0.08 = 0.055 × 1 × 6.8×10^-7/d

By cross multiplying, we have that

0.08 × d = 0.055 × 1 × 6.8×10^-7

d = 0.055 × 1 × 6.8×10^-7/ 0.08

d = 3.74 × 10^-7/ 0.08

d = 46.75×10^-7

d = 4.675×10^-6 m

attach the statements so i can answer : )

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.