What is the energy difference between the states with the nuclear spin angular momentum components parallel and antiparallel to the field?

Explanation:

The main difference is that states with spin angular momentum in the same direction of the field are more high energy that the states with antiparallel spin agular momentum.

The energy for a particular level is

E = -(γ*h/2*π)*m*B

where γ is a constant about magnetic moment, h is the Planck constant, m is the state level and B is the strength of the magnetic field. Its clear that for antiparallel spins m=-1/2 the energy is lower in comparisson with states with m=1/2

In fact

ΔE = γ*h*B/2*π

Refer below for the explanation.

Explanation:

The principle distinction is that states with turn precise force a similar way of the field are all the more high vitality that the states with antiparallel turn agular energy.

E = - (γ*h/2*π)*m*B,

where γ is a consistent about attractive minute, h is the Planck steady, m is the state level and B is the quality of the attractive field. Plainly for antiparallel twists m=-1/2 the vitality is lower in comparisson.

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pretty sure it's false