A tuning fork with a frequency of 404 Hertz is struck with a soft hammer. The fork is struck a second time by the
same hammer with twice as much force, and the volume, or amplitude, increases by a factor of two. What will the
frequency of the second sound be? (LT-7)

i don't know that i agree with that but what's the question ?

365.25 earth days are in the year of a light year

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m