A circuit consists of a 171- resistor and a 0.158-H inductor. These two elements are connected in series across a generator that has a frequency of 147 Hz and a voltage of 278 V. (a) What is the current in the circuit? (b) Determine the phase angle between the current and the voltage of the generator

a ) I= 1.635-i0.0021 b) ∅=   -0.074

Explanation:

a) reactive impeadance= 2πfL

                                 =2(3.14)(147)(0.158)

                                 =145.86 Ω

Z= 171+j145.86

I=V/Z

I=278/(171+j145.86)

I= 1.635-i0.0021

b) ∅=inv.tan (-0.0021/1.635)

 ∅=-0.074

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get