A raindrop acquires a charge of 4 x 10-18 C as it falls. The force of attraction when the

raindrop is 5.2 m from the bulb on the end of a car antenna is 5 x 10-11 N. What is the charge

on the end of the car antenna?

Explanation:

The charge of the raindrop  Q =

The charge on the bulb (q) = ???

The force (F)  =

The separation of the raindrop from the bulb = 5.2 m

However, the force of attraction between the charge is given by the Coulomb's Law which is expressed as:

where:

Coulomb's constant (k) =

Therefore, the charge on the end of the car antenna =

1/0.14nm = 10^10/1.4 a lot

f=ma newton

f=100x2.5=250n