Ice-skater slides toward a sled sitting on the ice and hits it. The skater exerts a 12.6 N force on the sled at an angle of 15.3° below the horizontal. The sled then moves 15.4 m forward. How much work did the skater do on the sled? Assume friction is negligible.

Knowns Unknown

F = d = W = ?

θ =

Solve for the Unknown

a. Write the equation for work
b. Insert known quantities

Expression of work done is

Work done to move the sled is given as 187.2 J

Explanation:

As we know that the formula of work done is given as

here we know that

F = 12.6 N

d = 15.4 m

so we will have

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.