A 15-µF capacitor and a 25-µF capacitor are connected in parallel, and charged to a potential difference of 60 V. How much energy is then stored in this capacitor combination?

Energy stored, E = 0.072 J

Explanation:

Given that,

Capacitance,

Capacitance,

These two capacitor are connected in parallel, and charged to a potential difference of, V = 60 volts

We know that in parallel combination of capacitor, the equivalent capacitance is given by :

The energy stored in the capacitor is given by :

So, the energy stored in the capacitor in this capacitor combination is 0.072 J.

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explanation:

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