Around midcourse, a velocity adjustment is performed to eliminate the small errors introduced when departing from Earth's orbit. This adjustment is performed using one of the onboard thrusters. At the location where the adjustment is made, the velocity is 26248 m/s and should be 27000 m/s. Knowing that the thruster used for the maneuver generates a thrust of F= 7540 N, determine how long, in minutes, it should be turned on to adjust the velocity. The mass of the spacecraft is 2000 kg.

Explanation:

Given:

Initial velocity, vi = 26248 m/s

Final velocity, vf = 27000 m/s

Force, f = 7540 N

Mass, m = 2000 kg

Force = mass × acceleration

= mass × change in velocity/time

Change in velocity = vf - vi

Time, t = (2000 × (27000 - 26248))/7540

= 199.47 s.

I min = 60 sec

Tine, t = 3.325 min

= 3.33 min.

dang that balls went far

report!

explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."