A ship sets sail from Rotterdam, The Netherlands, heading due north at 8.00 m/s relative to the water. The local ocean current is 1.52 m/s in a direction 40° north of east. What is the velocity of the ship relative to the earth?.

The velocity of the ship relative to the earth V = 9.05

Explanation:

The local ocean current is  = 1.52 m/s

Direction = 40°

Velocity component in X - direction = 1.52 °

= 1.164

Velocity component in Y - direction = 8 + 1.52 °

= 8.97

The velocity of the ship relative to the earth

Put the values of and we get,

⇒

⇒ V = 9.05

This is the velocity of the ship relative to the earth.

f=ma newton's second law 7x8=56n