A particle (charge 7.5 µC) is released from rest at a point on the x axis, x = 10 cm. It begins to move due to the presence of a 2.0-µC charge which remains fixed at the origin. What is the kinetic energy of the particle at the instant it passes the point x = 1.0 m? Group of answer choices 1.8 J 1.2 J 2.4 J 1.4 J 3.0 J

1.2 J

Explanation:

First of all, we have to take into account that at the beginning all energy is electrostatic potential

Ep = K*q1*q2/r = Et "total energy"

where r is the distance between charges. The total energy must conserve, hence, if we calculate the potential energy for x = 1.0 cm = 0.1 m, we can find the kinetic energy by subtracting the potential energy for x = 1.0m from the initial potential energy. In other words:

The energy for x = 0.1m is the total energy

Et = Ep = 8.98*10^(9)*7.5*10^(-6)*2.0*10^(-6)/0.1 = 1.35 J

The potential  energy for x=1m

Ep' = 8.98*10^(9)*7.5*10^(-6)*2.0*10^(-6)/1 = 0.135 J

The kinetic energy is:

Et = Ep' + Ek

Ek = Et - Ep = 1.35 J - 0.135 J = 1.21 J ≅ 1.2 J

for i will definitly keep him in my prayers. may god bles you and your

plz mark me as brainliest

have an amazing day

grav forces affect all objects magnetic forces affect magnetic objects and electric currents