A negative charge, q1, of 6 µC is 0.002 m north of a positive charge, q2, of 3 µC. What is the magnitude and direction of the electrical force, Fe, applied by q1 on q2?

Force,F =

Explanation:

Given that,

Charge 1,

Charge 2,

Negative charge is 0.002 m north of a positive charge, distance between charges, d = 0.002 m.

Let is the magnitude of electrical force applied by q₁ on q₂. We know that the electrical force is given by the formula as follows :

So, the electrical force applied by q₁ on q₂ is towards north.

b) 10 minutes

girls stopped for 10 minutes.

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.