An object 8.25 cm from a lens creates a virtual image of magnification 2.40 what is the focal length of the lens (mind your minus sign) (unit=cm)

The focal length of the lens is 14.1428 cm and it is a positive focal length. The lens is convex.

Given information:

The object distance is cm.

The magnification of the lens is

So, the image distance will be calculated as,

Now, use the lens formula to calculate the focal length f of the lens.

Therefore, the focal length of the lens is 14.1428 cm and it is a positive focal length. The lens is convex.

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Focal length of the lens is 14.14 cm

Explanation:

As we know that the image formed due to lens is virtual image

so here we have

M = 2.40

now we have

now we have

distance of object is 8.25 cm

so we have

now by lens formula

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

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