The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by
Q(t)=t3−2t2+4t+4

Find the current when t = 1s. At what time is the current lowest?

Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

At t = 1 s,

Current,

So, the current at t = 1 s is 3 A.

For lowest current,

Hence, this is the required solution.

like poles repel so keep pushing north to north and repels funny to see this

it is called kinetic energy