How much force is used if ms Johnston can bench press 123 kg in 3 seconds, using 2500 j of work? The total distance from the barbell to ms Johnston to the original starting position is 1.2m.

The force applied would be 2083.3N

Explanation:

Given:

Mass, m = 123kg

Time, t = 3 seconds

Work, W = 2500J

Distance, x = 1.2m

Force, F = ?

We know:

Work = Force X distance

Therefore, the force applied would be 2083.3N

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.