A 0.46 kg mass is attached to a light spring with a force constant of 39.9 N/m and set into oscillation on a horizontal frictionless surface. If the spring is stretched 5.0 cm and released from rest, determine the following. (a) maximum speed of the oscillating mass

0.466 m/s

Explanation:

We are given that

Mass =m=0.46 kg

Spring constant,k=39.9 N/m

Length of stretched spring=A=5 cm=

1 m=100 cm

a.We have to find the maximum speed of the oscillating mass.

Maximum speed,v=

Using the formula

Maximum speed,v=

Maximum speed,v=0.466 m/s

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)