Jack and Jill are maneuvering a 3300 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is 1.1m/s. As the boat moves to position < 4, 0, 2 > m, Jack exerts a force of < -420, 0, 210 > N, and Jill exerts a force of <180, 0, 360 > N. How much work does Jack do?WJack = JHow much work does Jill do?WJill = JWhat is the final speed of the boat?vf = m/s

The workdone by Jack is  

The workdone by Jill is  

The final velocity is  

Explanation:

From the question we are given that

          The mass of the boat is

          The initial position of the boat is  

           The Final position of the boat is  

           The Force exerted by Jack

             The Force exerted by Jill  

Now to obtain the displacement made we are to subtract the final position from the initial position

Now that we have obtained the displacement we can obtain the Workdone

  which is mathematically represented as

 The amount of workdone by jack would be

  The amount of workdone by Jill would be

According to work energy theorem the Workdone is equal to the kinetic energy of the boat

the higher the current the higher the mag field around it the higher the influence on the compass