A simple pendulum consists of a 4.9-kg mass attached to a string. The pendulum is pulled to the right and held at rest so that it is 2.08 m above the lowest point in its swing. If you let it go from this point, how fast (in m/s) is it traveling at the lowest point of its swing (on the initial pass)

6.384 m/

Explanation:

The velocity is given by;

We know;

PE= mgh

KE= 1/2 m

but KE=PE

==> 1/2 m =mgh

==> 1/2 =gh

==>

puting g=9.8 m/sec2

h=2.08 m

==> =

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

there are no contact forces mentioned on the list of choices that you've provided.