On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 78.4 cm and diameter 2.30 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g

24.9 N

Explanation:

Parameters Given:

Length of cylinder, h = 78.4 cm = 0.784 m

Diameter of cylinder = 2.3 cm = 0.023 m

Radius of cylinder, r = 0.0115m

Density of rod = 7800 kg/m³

Desnity is given as:

Density = mass/volume

Volume of cylindrical rod is:

Volume = pi * r² * h

= 3.142 * 0.0115² * 0.784

= 0.00326 m³

Therefore, mass can be gotten:

Mass = Density * volume

Mass = 7800 * 0.000326

Mass = 2.54 kg

Weight is given as:

Weight = mass * acceleration due to gravity

Weight = 2.54 * 9.8

Weight = 24.9 N

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2