A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vector. Ignoring the particle's weight, what type of path will the particle follow? A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vector. Ignoring the particle's weight, what type of path will the particle follow? The charged particle will follow a spiral path. The charged particle will follow a parabolic path. The charged particle will follow a straight-line path. The charged particle will follow a circular path.

The charged particle will follow a circular path.

Explanation:

The expression for the magnetic force due to the charged particle is as follows;

Here, q is the charge, B is the magnetic field, v is the velocity, is the angle between velocity and magnetic force and F is the magnetic force.

If the direction of velocity has both perpendicular and parallel components to the direction magnetic field then the parallel component moves the charged particle in a straight line and the perpendicular component moves the charged particle in a circular direction. Then, the trajectory followed by the charged particle is helix.

In the given problem, a charged particle moves in the uniform magnetic field in such a way velocity vector of the charged particle is perpendicular to the magnetic field vector.

Here, and the magnetic force is constant.

Then, the magnitude of magnetic force becomes, F= qvB. In this case, the force will be maximum. If the charged particle moves along the direction of  magnetic field then the F=0 as .

Therefore, the path followed by the charged particle is circular path.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.