A ball rolling across the floor at a velocity of 6.15 m/s [E] slows to rest in 1.00 minute. The
acceleration of the ball is m/s? [E]. Record your answer to 3 significant digits.

0.102m/s^2

Explanation:

velocity of ball = 6.15 m/s

Time taken for ball to roll = 1.00 minute

Convert 1.00 minute to seconds

(Since 60 seconds = 1 minute, the time taken for ball to roll = 60 seconds

Acceleration of the ball = ? (Let unknown value be Z)

Since acceleration is the rate of change of velocity per unit time

i.e Acceleration = Velocity / Time

Z = (6.15 m/s / 60 seconds)

Z = 0.1025m/s^2

Round Z to 3 significant digits (Z = 0.102m/s^2)

Thus, the acceleration of the ball is 0.102 metres per second square

answer: its c lololo

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm