The moment of inertia of a thin ring of mass M and radius R about its symmetry axis is I C M = M R 2 . Kira is working the ring‑toss booth at a local carnival. While waiting for customers, Kira occupies her time by twirling one of the plastic rings of mass M and radius R about her finger. Model the motion of the plastic ring as a thin ring rotating about a point on its circumference. What is the moment of inertia of the plastic ring?

So total moment of inertia of the ring about its end is given as

Explanation:

As we know that the moment of inertia of the ring about its axis passing through COM is given by the formula

now we know that

if we wish to find the moment of inertia passing through an axis from its circumference which is parallel to the axis passing from COM is given by parallel axis theorem

So we will have

so here we have

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min