A particle that has a charge of 7.4 μC moves with a velocity of magnitude 3 × 105 m/s along the +x axis. It experiences no magnetic force, although there is a magnetic field present. The maximum possible magnetic force that the charge with the given speed could experience has a magnitude of 0.520 N. Find the magnitude and direction of the magnetic field. Note that there are two possible answers for the direction of the field.

Explanation:

F = qvB

Where F equal to the magnetic force on the particle.

q = charge on the particle

v = velocity of the particle

B =Magnetic field

F = 0.520N

q = 7.4 μC = 7.4×10-⁶C

v = 3×10⁵m/s

B= ?

B = F/qv

B = 0.520/(7.4×10-⁶ ×3×10⁵)

B = 0.234T.

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.